2018 WAEC General Maths Questions And Answers: Objectives & Theory

2018 WAEC General Maths Questions And Answers: Objectives & Theory – The Following Are Related To This. 2014 WAEC Mathematics Question And Answer, WAEC Questions And Answers On Mathematics 2015, 2015 WAEC Mathematics Theory, WAEC Mathematics Past Questions And Answers In Pdf, WAEC Questions And Answers On Mathematics 2017,  2016 WAEC Questions And Answers On Mathematics.
Others are GCE past questions on English language, WAEC Biology question and answer 2018, marking scheme for WAEC .maths, physics practical, and area of concentration for WAEC 2018. These are essential to your making  good grades in this 2018 May/June WAEC examinations to  qualify you for university admission this year. 2018 WAEC General Maths Questions And Answers: Objectives & Theory.
In this post are verified regularly repeated General Maths Objective and Theory questions and answers for 2018 May/June SSCE exam that holds on 18/4/2018.  Get them in your finger tips and you are sure of a high grade in this exams. 2018 WAEC General Maths Questions And Answers: Objectives & Theory.
2018 WAEC General Maths Questions And Answers: Objectives & Theory

2018 WAEC General Maths Questions And Answers: Objectives & Theory

WAEC FOR ALL

The West African Examinations Council (WAEC)  is the West African countries  Examination Body. It conducts the West African Senior School Certificate Examination for in-house school students and General Certificate Examination for private candidates in West African Countries. These are entry qualification examinations for higher education institutions in these countries.
As you know, no University, Polytechnic, or college of education in these countries would admit you into any of their courses without a good grade in any of these examinations. That is why over three million candidates register and take these subject exams annually.
Consequently, 2018 WAEC General Maths Questions And Answers: Objectives & Theory, our goal here is to help you achieve this your life dream. Listed here are Maths, Objective and Theory  questions and answers relevant to 18/4/2018 Maths Subject examination.
   

2018 WAEC General Maths Questions And Answers: Objectives & Theory

THE OBJECTIVES
Verified MATHS OBJ: 
1-10: BCABCADDAA  
11-20: DDEACDBACA  
21-30: ABAACECADB  
31-40: ACAEBEBBCD  
41-50: EDEDDEDDCA  
51-60: CADCEDDEAB

2018 WAEC General Maths Questions And Answers: Objectives & Theory

THEORY SESSION; 

(keys)
/ means DIVISION 
* means multiplication 
tita u should know dat. 
rais means raise to power 
^ means raise to power 
sqr rut/ squar rut means square root 
—-(1) means equation 1 
yr means year 
f(x-xbar) means x MINUS x BAR as in statistics which means that MINUS WILL BE ON TOP OF x. 
, (Comma) means NEXT LINE, (/quote)
(1) n(AUBUC)=n(A)+n(B)+n(C)-n(AnB)-n(BnC)+n(AnBnC) 
55=21+24+23-6-8-5+2x+x 
55=49+3x 
3x=6 
x=2 
(1i)  
21-6-5-x = 21-11-2 
physics only=8 
(1ii) 6+5+8= 19 
(2a) Using almighty formular 
x= -b+sqrt(b^2- 4ac)/2a 
=5+sqrt(25-4(2)(3))/2(2) 
=(5+1)/4 or (5-1)/4 
= 1 or (1)1/2 
(2b) Volume of cylinder= pieR^2h 
352=22/7*4*4*h 
h=7

Get past questions and answer here:

Economics
Biology
Maths

English
Physics
Further Maths
Geography
Food & Nut
Chemistry
2018 WAEC Time Table

2018 WAEC General Maths Questions And Answers: Objectives & Theory

2018 WAEC General Maths Questions And Answers: Objectives & Theory

(3a) RD^2=(37)^2- (12)^2 
 = 1369-144 
RD^2=1225 
RD=sqrt(1225) 
=35cm 
Area= 35*12=420cm^2 
(3b) ((2p+q)/(p-3q))^1/2=h 
sqrt(h)=(2p+q)/(p-3q) 
Psqrt(h)- 3qsqrt(h)=2p+q 
Psqrt(h)-2P= q+3qsqrt(h) 
P(sqrt(h)-2)= q+3qsqrt(h) 
P=q+3qsrt(h)/sqrt(h)-2 
(4a) (n-2)180= 
xn+x=180 
x(n+1) 
180n-360=xn+x 
180n-360=x(n+1) 
x=180n-360/n+1 
(4b) (x+5)/3-(2x-1)/5=5/6 
30((x+5)/3) – 30((2x-1)/5)= 30(5/6) 
10x + 50-12x+6=25 
56-2x=25 
-2x=-31 
x=15.5 
(5a) perimeter of sector= (tita/360)2pieR+2r 
=2(9)+120/360*2*22/7*9 
=18+18.86 
=36.9cm 
(5b) 150/h=tan30 
h=150/tan30 
h=259.8 approx 260
(6a) Snth= n/2(2a+11d) 
-192=24a+132d 
-96=12a+66d 
-32=4a+22d 
-16=2a+11d  —-equ(1) 
-252=18(2a+17d)/2 
-504=18(2a+17d) 
-28=2a+17d——-equ(2) 
(-16=2a+11d) 
-(-28=2a+17d) 
12=-6d 
d=-2 
(6b) from equ(1) 
-16=29+11(-2) 
-16=29-22 
2a=6 
a=3 
(6c) Tnth= a+(n-1)d 
=3+(15-1)(-2) 
T15th= -25 
T4th=a+(4-1)d 
=3+3(-2) 
=-3 
Product of 15th and 4th= -3*-25=75 
(7ai) STB= 180-75-40 
(sum of angles on a straight line) 
STB= 65 
SRP= 180-65(opposite angles are complementary) 
=115degree 
(7aii)  SQP= 115(angles substended from the same circumference are equal) 
(7aiii) 
SPQ=180-115-12 (sum of angle in a triangle) 
=53degree 
(7b) C=R+KT 
2800=R+K(6) 
2800= R+6k ———equ(1
– 3600= R+10K——equ(2) 
-800 = -4k 
k=200 
From eqn(1) 
2800=R+200(6) 
2800=1200R 
R=2(1/3) 
at 4hours, 
C= 2(1/3) + 200(4) 
= 800 +2(1/3) 
=802(1/3) 
=#802.3 
( 8 )  Distance from Airport to the North= Time*Speed  
= 500*1(1/2)= 750km  
2nd distance= xkm  
From cosine rule, a^2=b^2+c^2-2bc CosA  
x^2=750^2+400^2-2(750)(400)cos127  
=562500+160000-(-361089.01)  
x^2=1083589.01  
x=sqrt(1083589.01)= 1,040.96km  
Bearing from the airport  
from sine rule, a/sinA=b/sinB  
1040.96/sin127=750/sinb  
sinb=0.5754  
b=35.13  
d= 150-127-35.13(sum of anglesin a triangle)  
d= 17.89 approx = 17.9  
Bearing from the airport=180+17.9=197.9 

2018 WAEC General Maths Questions And Answers: Objectives & Theory

(9a) a^2= b^2+c^2(pythagora’s theorem) 
h^2=40^2+16^2 
=1600+256 
=1856 
h=sqrt(1856)= 43.1cm 
(9b) Total surface area 
Area of one of the four triangular faces=40*16=640cm^2 
for four triangles= 4*640=2560cm^2 
Area of square base=32*32=1024cm^2 
Total surface area=1024+2560=3584cm^2 
(12) TABULATE THE TABLE 
MARK%: 51-60, 61-60, 71-80, 81-90, 91-100 
BOUNDARIES: 50.5-60.5, 60.5-70.5, 70.5-80.5,80.5-90.5, 90.5-100.5 
CLASS MARK(X): 55.5,65.5,75.5,85.5,95.5 
FREQUENCY: 11, 23,39,17,10 
(FX): 610.5,1506.5,2944.5, 1453.5, 955 
/X-XBAR/: 19.2, 9.2, 0.8, 10.8, 20.8 
/X-XBAR/^2: 368.64, 84.64, 0.64, 116.64, 432.64 
F/X-XBAR/: 211.2, 211.6, 31.2, 183.6,208 
(i)  Mean= Efx/fx 
= (610.5+1506.5+2944.5+1453.5+955)/100 
=7470/100 
=74.7 approx =7 
(ii) Mean Deviation= sqrt(Ef/x-xbar/)/Efx 
sqrt(211.2+ 211.6+31.2+183.6+20 /100 
845.6/100=8.456 approx = 8 
(iii) Standard Deviation=sqrt(Ef/x-xbar/^2)/Efx 
sqrt(12336/100)=sqrt(123.36) 
=1

2018 WAEC General Maths Questions And Answers: Objectives & Theory

REQUIREMENTS:

If you desire further assistance, or have questions to ask, send them through the comment box on this page. Remember to share this through our social media share buttons below this page.
If you click to follow us on our Facebook handles you will ensure a regular update on matters that affect your performance on this.
Good luck.

2018 WAEC General Maths Questions And Answers: Objectives & Theory