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2018 WAEC General Maths Questions And Answers: Objectives & Theory

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Others are GCE past questions on English language, WAEC Biology question and answer 2018, marking scheme for WAEC .maths, physics practical, and area of concentration for WAEC 2018. These are essential to your making  good grades in this 2018 May/June WAEC examinations to  qualify you for university admission this year. 2018 WAEC General Maths Questions And Answers: Objectives & Theory.
In this post are verified regularly repeated General Maths Objective and Theory questions and answers for 2018 May/June SSCE exam that holds on 18/4/2018.  Get them in your finger tips and you are sure of a high grade in this exams. 2018 WAEC General Maths Questions And Answers: Objectives & Theory.
2018 WAEC General Maths Questions And Answers: Objectives & Theory

WAEC FOR ALL

The West African Examinations Council (WAEC)  is the West African countries  Examination Body. It conducts the West African Senior School Certificate Examination for in-house school students and General Certificate Examination for private candidates in West African Countries. These are entry qualification examinations for higher education institutions in these countries.
As you know, no University, Polytechnic, or college of education in these countries would admit you into any of their courses without a good grade in any of these examinations. That is why over three million candidates register and take these subject exams annually.
Consequently, 2018 WAEC General Maths Questions And Answers: Objectives & Theory, our goal here is to help you achieve this your life dream. Listed here are Maths, Objective and Theory  questions and answers relevant to 18/4/2018 Maths Subject examination.

2018 WAEC General Maths Questions And Answers: Objectives & Theory

THE OBJECTIVES
Verified MATHS OBJ:
1-10: BCABCADDAA
11-20: DDEACDBACA
21-30: ABAACECADB
31-40: ACAEBEBBCD
41-50: EDEDDEDDCA
51-60: CADCEDDEAB

THEORY SESSION;

(keys)
/ means DIVISION
* means multiplication
tita u should know dat.
rais means raise to power
^ means raise to power
sqr rut/ squar rut means square root
—-(1) means equation 1
yr means year
f(x-xbar) means x MINUS x BAR as in statistics which means that MINUS WILL BE ON TOP OF x.
, (Comma) means NEXT LINE, (/quote)
(1) n(AUBUC)=n(A)+n(B)+n(C)-n(AnB)-n(BnC)+n(AnBnC)
55=21+24+23-6-8-5+2x+x
55=49+3x
3x=6
x=2
(1i)
21-6-5-x = 21-11-2
physics only=8
(1ii) 6+5+8= 19
(2a) Using almighty formular
x= -b+sqrt(b^2- 4ac)/2a
=5+sqrt(25-4(2)(3))/2(2)
=(5+1)/4 or (5-1)/4
= 1 or (1)1/2
(2b) Volume of cylinder= pieR^2h
352=22/7*4*4*h
h=7

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2018 WAEC General Maths Questions And Answers: Objectives & Theory

2018 WAEC General Maths Questions And Answers: Objectives & Theory

(3a) RD^2=(37)^2- (12)^2
 = 1369-144
RD^2=1225
RD=sqrt(1225)
=35cm
Area= 35*12=420cm^2
(3b) ((2p+q)/(p-3q))^1/2=h
sqrt(h)=(2p+q)/(p-3q)
Psqrt(h)- 3qsqrt(h)=2p+q
Psqrt(h)-2P= q+3qsqrt(h)
P(sqrt(h)-2)= q+3qsqrt(h)
P=q+3qsrt(h)/sqrt(h)-2
(4a) (n-2)180=
xn+x=180
x(n+1)
180n-360=xn+x
180n-360=x(n+1)
x=180n-360/n+1
(4b) (x+5)/3-(2x-1)/5=5/6
30((x+5)/3) – 30((2x-1)/5)= 30(5/6)
10x + 50-12x+6=25
56-2x=25
-2x=-31
x=15.5
(5a) perimeter of sector= (tita/360)2pieR+2r
=2(9)+120/360*2*22/7*9
=18+18.86
=36.9cm
(5b) 150/h=tan30
h=150/tan30
h=259.8 approx 260
(6a) Snth= n/2(2a+11d)
-192=24a+132d
-96=12a+66d
-32=4a+22d
-16=2a+11d  —-equ(1)
-252=18(2a+17d)/2
-504=18(2a+17d)
-28=2a+17d——-equ(2)
(-16=2a+11d)
-(-28=2a+17d)
12=-6d
d=-2
(6b) from equ(1)
-16=29+11(-2)
-16=29-22
2a=6
a=3
(6c) Tnth= a+(n-1)d
=3+(15-1)(-2)
T15th= -25
T4th=a+(4-1)d
=3+3(-2)
=-3
Product of 15th and 4th= -3*-25=75
(7ai) STB= 180-75-40
(sum of angles on a straight line)
STB= 65
SRP= 180-65(opposite angles are complementary)
=115degree
(7aii)  SQP= 115(angles substended from the same circumference are equal)
(7aiii)
SPQ=180-115-12 (sum of angle in a triangle)
=53degree
(7b) C=R+KT
2800=R+K(6)
2800= R+6k ———equ(1)
– 3600= R+10K——equ(2)
-800 = -4k
k=200
From eqn(1)
2800=R+200(6)
2800=1200R
R=2(1/3)
at 4hours,
C= 2(1/3) + 200(4)
= 800 +2(1/3)
=802(1/3)
=#802.3
( 8 )  Distance from Airport to the North= Time*Speed
= 500*1(1/2)= 750km
2nd distance= xkm
From cosine rule, a^2=b^2+c^2-2bc CosA
x^2=750^2+400^2-2(750)(400)cos127
=562500+160000-(-361089.01)
x^2=1083589.01
x=sqrt(1083589.01)= 1,040.96km
Bearing from the airport
from sine rule, a/sinA=b/sinB
1040.96/sin127=750/sinb
sinb=0.5754
b=35.13
d= 150-127-35.13(sum of anglesin a triangle)
d= 17.89 approx = 17.9
Bearing from the airport=180+17.9=197.9

2018 WAEC General Maths Questions And Answers: Objectives & Theory

(9a) a^2= b^2+c^2(pythagora’s theorem)
h^2=40^2+16^2
=1600+256
=1856
h=sqrt(1856)= 43.1cm
(9b) Total surface area
Area of one of the four triangular faces=40*16=640cm^2
for four triangles= 4*640=2560cm^2
Area of square base=32*32=1024cm^2
Total surface area=1024+2560=3584cm^2
(12) TABULATE THE TABLE
MARK%: 51-60, 61-60, 71-80, 81-90, 91-100
BOUNDARIES: 50.5-60.5, 60.5-70.5, 70.5-80.5,80.5-90.5, 90.5-100.5
CLASS MARK(X): 55.5,65.5,75.5,85.5,95.5
FREQUENCY: 11, 23,39,17,10
(FX): 610.5,1506.5,2944.5, 1453.5, 955
/X-XBAR/: 19.2, 9.2, 0.8, 10.8, 20.8
/X-XBAR/^2: 368.64, 84.64, 0.64, 116.64, 432.64
F/X-XBAR/: 211.2, 211.6, 31.2, 183.6,208
(i)  Mean= Efx/fx
= (610.5+1506.5+2944.5+1453.5+955)/100
=7470/100
=74.7 approx =7
(ii) Mean Deviation= sqrt(Ef/x-xbar/)/Efx
sqrt(211.2+ 211.6+31.2+183.6+20 /100
845.6/100=8.456 approx = 8
(iii) Standard Deviation=sqrt(Ef/x-xbar/^2)/Efx
sqrt(12336/100)=sqrt(123.36)
=1

2018 WAEC General Maths Questions And Answers: Objectives & Theory

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Ane

Deacon Anekperechi Nworgu, a seasoned economist who transitioned into a chartered accountant, auditor, tax practitioner, and business consultant, brings with him a wealth of industry expertise spanning over 37 years.

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